A car stars from rest and accelerates at a constant rate in a straight line. In the first second the car covers a distance of 2.0 meters. How much additional distance will the car cover during the second of its motion?
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How Much Additional Distance Will The Car Cover During The Second Of Its Motion?2 comments to How Much Additional Distance Will The Car Cover During The Second Of Its Motion? |
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Initial velocity = 0 m/s
Acceleration = ?
Displacement = 2.0 m
Time = 1 s
Displacement = (Init. Vel.)(Time)+(1/2)(Accel.)(Time^2)
Acceleration = 2[Displacement-(Init. Vel.)(Time)]/(Time^2)
Acceleration = 2*(2 m)/(1 s^2) = 4.0 m/s/s
Displacement one second later (from t=1 to t=2):
Velocity(1 sec) = Acceleration*Time = (4.0 m/s/s)(1 s) = 4 m/s
Displacement = ?
TIme = 1 sec
Acceleration = 4 m/s/s
Displacement = (4 m/s)(1 s)+(4.0 m/s/s)(1 s^2) = 8 m
Overall Displacement = 2.0 m + 8.0 m = 10.0 m
i think an additional 4 meters making 6 meters in 2 seconds. Based on acceleration seeming to be +2 m/s/s